Re: [cpp] 关于const char * const &

[胡 玮]

应该是指针的引用，这个指针指向一个const，但我很奇怪const char　*&不就行了，
为什么*&中间还要加个const，要知道引用只能初始化，从偏译器的角度看本身就是个
常量没有必要再加const，这样看起来很怪

>From: 孙华明 <sunhm at neusoft.com>
>Reply-To: C++ Discuss Group <cpp at codingnow.com>
>To: C++ Discuss Group <cpp at codingnow.com>
>Subject: Re: [cpp] 关于const char * const &
>Date: Wed, 19 Jul 2006 17:16:45 +0800
>
>const char* const& a；
>这个声明是什么意思啊？
>这么复杂！
>   ----- Original Message -----
>   From: ling
>   To: C++ Discuss Group
>   Sent: Wednesday, July 19, 2006 4:12 PM
>   Subject: Re: [cpp] 关于const char * const &
>
>
>   不好意思，我知道原因了，应该是头文件iostream中有一个同名的函数min.
>
>   ----- Original Message -----
>     From: ling
>     To: C++ Discuss Group
>     Sent: Wednesday, July 19, 2006 5:04 PM
>     Subject: [cpp] 关于const char * const &
>
>
>
>     请问下面代码的函数min和min1有什么区别啊。
>     为什么函数min取得的比较结果不对呢？另外如果数组a,b的声明
>     前面加上const的话，函数min取得的结果就对了。
>     函数min1不管有没有const都能得到正确的结果。
>
>     #include <cstring>
>     #include <iostream>
>     using namespace std;
>
>     const char* const& min(const char* const& a, const char* const& b)
>     {
>      cout << "a = " << a << endl;
>      cout << "b = " << b << endl;
>      return (strcmp(a, b) < 0) ? a : b;
>     }
>
>     const char* const min1(const char* const a, const char* const b)
>     {
>      return (strcmp(a, b) < 0) ? a : b;
>     }
>
>     int main()
>     {
>      char a[] = "123";
>      char b[] = "456";
>
>      cout << min(a, b) << endl;
>       cout << min1(a, b) << endl;
>     }
>
>
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