Re: [cpp] 关于const char * const &

[孙华明]

typedef const char * const con_pointer_char_con;  //指向常量的常量指针。
con_pointer_char_con &a;

可能是指向常量的常量指针的引用。

----- Original Message ----- 
From: "胡 玮" <zorro0799 at hotmail.com>
To: <cpp at codingnow.com>
Sent: Wednesday, July 19, 2006 5:36 PM
Subject: Re: [cpp] 关于const char * const &


> 应该是指针的引用，这个指针指向一个const，但我很奇怪const char　*&不就行了，
> 为什么*&中间还要加个const，要知道引用只能初始化，从偏译器的角度看本身就是个
> 常量没有必要再加const，这样看起来很怪
> 
> >From: 孙华明 <sunhm at neusoft.com>
> >Reply-To: C++ Discuss Group <cpp at codingnow.com>
> >To: C++ Discuss Group <cpp at codingnow.com>
> >Subject: Re: [cpp] 关于const char * const &
> >Date: Wed, 19 Jul 2006 17:16:45 +0800
> >
> >const char* const& a；
> >这个声明是什么意思啊？
> >这么复杂！
> >   ----- Original Message -----
> >   From: ling
> >   To: C++ Discuss Group
> >   Sent: Wednesday, July 19, 2006 4:12 PM
> >   Subject: Re: [cpp] 关于const char * const &
> >
> >
> >   不好意思，我知道原因了，应该是头文件iostream中有一个同名的函数min.
> >
> >   ----- Original Message -----
> >     From: ling
> >     To: C++ Discuss Group
> >     Sent: Wednesday, July 19, 2006 5:04 PM
> >     Subject: [cpp] 关于const char * const &
> >
> >
> >
> >     请问下面代码的函数min和min1有什么区别啊。
> >     为什么函数min取得的比较结果不对呢？另外如果数组a,b的声明
> >     前面加上const的话，函数min取得的结果就对了。
> >     函数min1不管有没有const都能得到正确的结果。
> >
> >     #include <cstring>
> >     #include <iostream>
> >     using namespace std;
> >
> >     const char* const& min(const char* const& a, const char* const& b)
> >     {
> >      cout << "a = " << a << endl;
> >      cout << "b = " << b << endl;
> >      return (strcmp(a, b) < 0) ? a : b;
> >     }
> >
> >     const char* const min1(const char* const a, const char* const b)
> >     {
> >      return (strcmp(a, b) < 0) ? a : b;
> >     }
> >
> >     int main()
> >     {
> >      char a[] = "123";
> >      char b[] = "456";
> >
> >      cout << min(a, b) << endl;
> >       cout << min1(a, b) << endl;
> >     }
> >
> >
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